KMV's sigma - a note
According to the KMV1 model, the standard deviation for the default of the \(i\)th borrower \(\sigma_{Di}\) is given by \(\sigma_{Di}=\sqrt{(EDF)(1-EDF)}\) where \(EDF\) is the expected default frequency.
Specifically, let \(p\) be the probability of complete repayment of the loan, and \((1-p)\) be the probability of default, or the expected default frequency (EDF)
Probability of repayment
A Bernoulli trial2, repayment \(p\) returns 1 and default \((1-p)\) returns 0
Expected outcome:
$$ E(\mbox{payoff}) = 1 \times p + 0 \times (1-p)=p$$Standard deviation:
\begin{align*}\sigma & =\sqrt{(1-p)^2 \times p + (0-p)^2 \times (1-p)} \\ & =\sqrt{(1-2p + p^2) \times p + p^2 \times (1-p)} \\ & =\sqrt{(p-2p^2 + p^3) + (p^2 -p^3)} \\ & =\sqrt{p-p^2} \\ & =\sqrt{p(1-p)} \end{align*}Probability of default
A Bernoulli trial3, repayment (EDF) returns 0 and default (1-EDF) returns 1
Expected outcome:
$$ E(\mbox{payoff}) = 0 \times EDF + 1 \times (1 - EDF)= 1 - EDF $$Standard deviation:
\begin{align*}\sigma & =\sqrt{(0 - (1 - EDF)^2 \times EDF + (1 - (1 - EDF))^2 \times (1 - EDF)} \\ & =\sqrt{(-1 + EDF)^2 \times EDF + EDF^2 \times (1-EDF)} \\ & =\sqrt{(1-2EDF + EDF^2) \times EDF + EDF^2 - EDF^3} \\ & =\sqrt{EDF - 2EDF^2 + EDF^3 + EDF^2 - EDF^3} \\ & =\sqrt{EDF - EDF^2} \\ & =\sqrt{EDF(1-EDF)} \end{align*}Notes
- The KMV model is named after Stephen Kealhofer, John McQuown and Oldrich Vasicek. The model was acquired by Moody's Analytics in 2002
- Saunders and Cornett (2010, p330)
- KMV
References
- Saunders A and M Cornett, (2010), Financial institutions management: a risk management approach, 7 ed., McGraw-Hill
- Published: 23 July 2014
- Revised: Saturday 25th of February 2023 - 10:13 AM, [Australian Eastern Standard Time (EST)]